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#!/usr/bin/env python3
# MIT License
#
# Copyright (c) 2023 Eugenio Parodi <ceccopierangiolieugenio AT googlemail DOT com>
#
# Permission is hereby granted, free of charge, to any person obtaining a copy
# of this software and associated documentation files (the "Software"), to deal
# in the Software without restriction, including without limitation the rights
# to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
# copies of the Software, and to permit persons to whom the Software is
# furnished to do so, subject to the following conditions:
#
# The above copyright notice and this permission notice shall be included in all
# copies or substantial portions of the Software.
#
# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
# IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
# FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
# AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
# LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
# OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
# SOFTWARE.
# This test is bases on the example in:
# https://www.geeksforgeeks.org/python-consecutive-characters-frequency/
import sys, os
import timeit
from itertools import groupby
sys.path.append(os.path.join(sys.path[0],'../..'))
testString1 = "EugenioXXXXXXXXXXXXXXXXXXParodiYYYYYYmalleoloZZZZsassso_______________122333444455555666666777777888888889999999990000000000"
def process1(txt):
ret = ""
for ch in txt:
ret += ch
return ret
def process2(txt):
# return ''.join([ch*l if (l:=len(list(j)))>4 else f"[{l}b{ch}" for ch, j in groupby(txt)])
return ''.join([ch*l if (l:=len(list(j)))<=4 else f"[{l}b{ch}" for ch, j in groupby(txt)])
def process3(txt):
chBk = txt[0]
count = 0
ret = ""
for ch in txt:
if ch == chBk:
count +=1
else:
if count>4:
ret += f"[{count}b{chBk}"
else:
ret += chBk*count
chBk = ch
count = 1
if count>4:
ret += f"[{count}b{chBk}"
else:
ret += chBk*count
return ret
def process4(txt):
chBk = txt[0]
count = 0
ret = ""
# genStr = (c for c in txt)
genStr = iter(txt)
ch = next(genStr)
while ch:
count = 1
while ch == (_ch:=next(genStr,None)):
count +=1
if count>4:
ret += f"[{count}b{ch}"
else:
ret += ch*count
ch = _ch
# if count>4:
# ret += f"[{count}b{ch}"
# else:
# ret += ch*count
return ret
def test1(): return process1(testString1)
def test2(): return process2(testString1)
def test3(): return process3(testString1)
def test4(): return process4(testString1)
loop = 100000
a={}
iii = 1
while (testName := f'test{iii}') and (testName in globals()):
result = timeit.timeit(f'{testName}(*a)', globals=globals(), number=loop)
# print(f"test{iii}) fps {loop / result :.3f} - s {result / loop:.10f} - {result / loop} {globals()[testName](*a)}")
print(f"test{iii:02}) | {result / loop:.10f} sec. | {loop / result : 15.3f} Fps ╞╡-> {globals()[testName](*a)}")
iii+=1